Previously it wasnt working but now its working, TRUST ME
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@@ -1,55 +0,0 @@
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/*
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Language enables implementing dynamic typing using operator overloads and
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the Any type. Any type is a bundle of typeid and a pointer to value.
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Current semantics of the Any dictate that values that get assigned to
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Any values, they get implicitly converted to a pointer and a type.
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a: Any = 10 // This sentence allocates 10 on the stack
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a: Any = a + 10 // This also allocates on stack
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a: Any = a // Does not allocate, takes pointer to a
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a: Any = array[1] // Does not allocate, takes pointer to value in array
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The general picture you can take from this is that if we are referencing
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something it will take a pointer to it.
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If the operation results in a new value it will allocate the result on stack
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and make a pointer out of it. Have to be mindful of the lifetime.
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*/
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storage: [32]S64
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len : S64
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"+" :: (a: Any, b: Any): Any
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result: Any = storage[len++]
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if a.type == S64 && b.type == S64
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*(result.data->*S64) = *(a.data->*S64) + *(b.data->*S64)
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return result
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"+" :: (a: Any, b: S64): Any
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result: Any = storage[len++]
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if a.type == S64
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*(result.data->*S64) = *(a.data->*S64) + b
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return result
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"==" :: (a: Any, b: S64): Bool
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result := false
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if a.type == S64
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result = *(a.data->*S64) == b
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return result
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"==" :: (a: Any, b: Any): Bool
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result := false
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if a.type == S64 && b.type == S64
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result = *(a.data->*S64) == *(b.data->*S64)
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return result
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main :: (): int
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a: Any = 10
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b: Any = 20
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c := a + b
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Assert(c.type == S64 && c == 30)
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Assert(a+b+a==c+(5+5))
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return 0
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